3(k-2)-6=4k-3k-1

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Solution for 3(k-2)-6=4k-3k-1 equation: 



3(k-2)-6=4k-3k-1

We move all terms to the left:

3(k-2)-6-(4k-3k-1)=0

We add all the numbers together, and all the variables

3(k-2)-(k-1)-6=0

We multiply parentheses

3k-(k-1)-6-6=0

We get rid of parentheses

3k-k+1-6-6=0

We add all the numbers together, and all the variables

2k-11=0

We move all terms containing k to the left, all other terms to the right

2k=11

k=11/2

k=5+1/2

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