3(k-2)-6=6-(5k-1)

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Solution for 3(k-2)-6=6-(5k-1) equation: 



3(k-2)-6=6-(5k-1)

We move all terms to the left:

3(k-2)-6-(6-(5k-1))=0

We multiply parentheses

3k-(6-(5k-1))-6-6=0



We calculate terms in parentheses: -(6-(5k-1)), so:

6-(5k-1)

determiningTheFunctionDomain
-(5k-1)+6

We get rid of parentheses

-5k+1+6

We add all the numbers together, and all the variables

-5k+7

Back to the equation:

-(-5k+7)



We add all the numbers together, and all the variables

3k-(-5k+7)-12=0

We get rid of parentheses

3k+5k-7-12=0

We add all the numbers together, and all the variables

8k-19=0

We move all terms containing k to the left, all other terms to the right

8k=19

k=19/8

k=2+3/8

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