3(k-2)-7=3k-(2k-3)

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Solution for 3(k-2)-7=3k-(2k-3) equation:


Simplifying
3(k + -2) + -7 = 3k + -1(2k + -3)

Reorder the terms:
3(-2 + k) + -7 = 3k + -1(2k + -3)
(-2 * 3 + k * 3) + -7 = 3k + -1(2k + -3)
(-6 + 3k) + -7 = 3k + -1(2k + -3)

Reorder the terms:
-6 + -7 + 3k = 3k + -1(2k + -3)

Combine like terms: -6 + -7 = -13
-13 + 3k = 3k + -1(2k + -3)

Reorder the terms:
-13 + 3k = 3k + -1(-3 + 2k)
-13 + 3k = 3k + (-3 * -1 + 2k * -1)
-13 + 3k = 3k + (3 + -2k)

Reorder the terms:
-13 + 3k = 3 + 3k + -2k

Combine like terms: 3k + -2k = 1k
-13 + 3k = 3 + 1k

Solving
-13 + 3k = 3 + 1k

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-1k' to each side of the equation.
-13 + 3k + -1k = 3 + 1k + -1k

Combine like terms: 3k + -1k = 2k
-13 + 2k = 3 + 1k + -1k

Combine like terms: 1k + -1k = 0
-13 + 2k = 3 + 0
-13 + 2k = 3

Add '13' to each side of the equation.
-13 + 13 + 2k = 3 + 13

Combine like terms: -13 + 13 = 0
0 + 2k = 3 + 13
2k = 3 + 13

Combine like terms: 3 + 13 = 16
2k = 16

Divide each side by '2'.
k = 8

Simplifying
k = 8

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