3(k-2)-7=6k-(5k-2)

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Solution for 3(k-2)-7=6k-(5k-2) equation: 



3(k-2)-7=6k-(5k-2)

We move all terms to the left:

3(k-2)-7-(6k-(5k-2))=0

We multiply parentheses

3k-(6k-(5k-2))-6-7=0



We calculate terms in parentheses: -(6k-(5k-2)), so:

6k-(5k-2)

We get rid of parentheses

6k-5k+2

We add all the numbers together, and all the variables

k+2

Back to the equation:

-(k+2)



We add all the numbers together, and all the variables

3k-(k+2)-13=0

We get rid of parentheses

3k-k-2-13=0

We add all the numbers together, and all the variables

2k-15=0

We move all terms containing k to the left, all other terms to the right

2k=15

k=15/2

k=7+1/2

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