3(k-2)12=k6

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Solution for 3(k-2)12=k6 equation: 



3(k-2)12=k6

We move all terms to the left:

3(k-2)12-(k6)=0

We add all the numbers together, and all the variables

-1k^6+3(k-2)12=0

We multiply parentheses

-1k^6+36k-72=0

We do not support ekpression: k^6

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