3(k-2)=-(2k+16)

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Solution for 3(k-2)=-(2k+16) equation: 



3(k-2)=-(2k+16)

We move all terms to the left:

3(k-2)-(-(2k+16))=0

We multiply parentheses

3k-(-(2k+16))-6=0



We calculate terms in parentheses: -(-(2k+16)), so:

-(2k+16)

We get rid of parentheses

-2k-16

Back to the equation:

-(-2k-16)



We get rid of parentheses

3k+2k+16-6=0

We add all the numbers together, and all the variables

5k+10=0

We move all terms containing k to the left, all other terms to the right

5k=-10

k=-10/5

k=-2

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