3(k-4)+2k=k+4

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Solution for 3(k-4)+2k=k+4 equation: 



3(k-4)+2k=k+4

We move all terms to the left:

3(k-4)+2k-(k+4)=0

We add all the numbers together, and all the variables

2k+3(k-4)-(k+4)=0

We multiply parentheses

2k+3k-(k+4)-12=0

We get rid of parentheses

2k+3k-k-4-12=0

We add all the numbers together, and all the variables

4k-16=0

We move all terms containing k to the left, all other terms to the right

4k=16

k=16/4

k=4

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