3(k-4)-2(k+1)-13=-19

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Solution for 3(k-4)-2(k+1)-13=-19 equation: 


Simplifying
3(k + -4) + -2(k + 1) + -13 = -19

Reorder the terms:
3(-4 + k) + -2(k + 1) + -13 = -19
(-4 * 3 + k * 3) + -2(k + 1) + -13 = -19
(-12 + 3k) + -2(k + 1) + -13 = -19

Reorder the terms:
-12 + 3k + -2(1 + k) + -13 = -19
-12 + 3k + (1 * -2 + k * -2) + -13 = -19
-12 + 3k + (-2 + -2k) + -13 = -19

Reorder the terms:
-12 + -2 + -13 + 3k + -2k = -19

Combine like terms: -12 + -2 = -14
-14 + -13 + 3k + -2k = -19

Combine like terms: -14 + -13 = -27
-27 + 3k + -2k = -19

Combine like terms: 3k + -2k = 1k
-27 + 1k = -19

Solving
-27 + 1k = -19

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '27' to each side of the equation.
-27 + 27 + 1k = -19 + 27

Combine like terms: -27 + 27 = 0
0 + 1k = -19 + 27
1k = -19 + 27

Combine like terms: -19 + 27 = 8
1k = 8

Divide each side by '1'.
k = 8

Simplifying
k = 8

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