3(k-4)-2(k+2)-13=22

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Solution for 3(k-4)-2(k+2)-13=22 equation:



3(k-4)-2(k+2)-13=22
We move all terms to the left:
3(k-4)-2(k+2)-13-(22)=0
We add all the numbers together, and all the variables
3(k-4)-2(k+2)-35=0
We multiply parentheses
3k-2k-12-4-35=0
We add all the numbers together, and all the variables
k-51=0
We move all terms containing k to the left, all other terms to the right
k=51

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