3(k-4)-2(k+2)-13=22

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Solution for 3(k-4)-2(k+2)-13=22 equation: 



3(k-4)-2(k+2)-13=22

We move all terms to the left:

3(k-4)-2(k+2)-13-(22)=0

We add all the numbers together, and all the variables

3(k-4)-2(k+2)-35=0

We multiply parentheses

3k-2k-12-4-35=0

We add all the numbers together, and all the variables

k-51=0

We move all terms containing k to the left, all other terms to the right

k=51

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