3(k-4)-2(k+2)-13=23

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Solution for 3(k-4)-2(k+2)-13=23 equation: 


Simplifying
3(k + -4) + -2(k + 2) + -13 = 23

Reorder the terms:
3(-4 + k) + -2(k + 2) + -13 = 23
(-4 * 3 + k * 3) + -2(k + 2) + -13 = 23
(-12 + 3k) + -2(k + 2) + -13 = 23

Reorder the terms:
-12 + 3k + -2(2 + k) + -13 = 23
-12 + 3k + (2 * -2 + k * -2) + -13 = 23
-12 + 3k + (-4 + -2k) + -13 = 23

Reorder the terms:
-12 + -4 + -13 + 3k + -2k = 23

Combine like terms: -12 + -4 = -16
-16 + -13 + 3k + -2k = 23

Combine like terms: -16 + -13 = -29
-29 + 3k + -2k = 23

Combine like terms: 3k + -2k = 1k
-29 + 1k = 23

Solving
-29 + 1k = 23

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '29' to each side of the equation.
-29 + 29 + 1k = 23 + 29

Combine like terms: -29 + 29 = 0
0 + 1k = 23 + 29
1k = 23 + 29

Combine like terms: 23 + 29 = 52
1k = 52

Divide each side by '1'.
k = 52

Simplifying
k = 52

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