3(k-4)=7k+4

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Solution for 3(k-4)=7k+4 equation: 



3(k-4)=7k+4

We move all terms to the left:

3(k-4)-(7k+4)=0

We multiply parentheses

3k-(7k+4)-12=0

We get rid of parentheses

3k-7k-4-12=0

We add all the numbers together, and all the variables

-4k-16=0

We move all terms containing k to the left, all other terms to the right

-4k=16

k=16/-4

k=-4

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