3(k-5)-2(k+2)-13=-24

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Solution for 3(k-5)-2(k+2)-13=-24 equation: 



3(k-5)-2(k+2)-13=-24

We move all terms to the left:

3(k-5)-2(k+2)-13-(-24)=0

We add all the numbers together, and all the variables

3(k-5)-2(k+2)+11=0

We multiply parentheses

3k-2k-15-4+11=0

We add all the numbers together, and all the variables

k-8=0

We move all terms containing k to the left, all other terms to the right

k=8

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