3(k-5)-2(k+2)-14=-27

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Solution for 3(k-5)-2(k+2)-14=-27 equation:



3(k-5)-2(k+2)-14=-27
We move all terms to the left:
3(k-5)-2(k+2)-14-(-27)=0
We add all the numbers together, and all the variables
3(k-5)-2(k+2)+13=0
We multiply parentheses
3k-2k-15-4+13=0
We add all the numbers together, and all the variables
k-6=0
We move all terms containing k to the left, all other terms to the right
k=6

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