3(k-5)-2(k+2)-14=-27

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Solution for 3(k-5)-2(k+2)-14=-27 equation: 



3(k-5)-2(k+2)-14=-27

We move all terms to the left:

3(k-5)-2(k+2)-14-(-27)=0

We add all the numbers together, and all the variables

3(k-5)-2(k+2)+13=0

We multiply parentheses

3k-2k-15-4+13=0

We add all the numbers together, and all the variables

k-6=0

We move all terms containing k to the left, all other terms to the right

k=6

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