3(k-5)-2(k+2)-14=24

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Solution for 3(k-5)-2(k+2)-14=24 equation: 



3(k-5)-2(k+2)-14=24

We move all terms to the left:

3(k-5)-2(k+2)-14-(24)=0

We add all the numbers together, and all the variables

3(k-5)-2(k+2)-38=0

We multiply parentheses

3k-2k-15-4-38=0

We add all the numbers together, and all the variables

k-57=0

We move all terms containing k to the left, all other terms to the right

k=57

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