3(k-5)-2(k+2)-14=27

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Solution for 3(k-5)-2(k+2)-14=27 equation: 


Simplifying
3(k + -5) + -2(k + 2) + -14 = 27

Reorder the terms:
3(-5 + k) + -2(k + 2) + -14 = 27
(-5 * 3 + k * 3) + -2(k + 2) + -14 = 27
(-15 + 3k) + -2(k + 2) + -14 = 27

Reorder the terms:
-15 + 3k + -2(2 + k) + -14 = 27
-15 + 3k + (2 * -2 + k * -2) + -14 = 27
-15 + 3k + (-4 + -2k) + -14 = 27

Reorder the terms:
-15 + -4 + -14 + 3k + -2k = 27

Combine like terms: -15 + -4 = -19
-19 + -14 + 3k + -2k = 27

Combine like terms: -19 + -14 = -33
-33 + 3k + -2k = 27

Combine like terms: 3k + -2k = 1k
-33 + 1k = 27

Solving
-33 + 1k = 27

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '33' to each side of the equation.
-33 + 33 + 1k = 27 + 33

Combine like terms: -33 + 33 = 0
0 + 1k = 27 + 33
1k = 27 + 33

Combine like terms: 27 + 33 = 60
1k = 60

Divide each side by '1'.
k = 60

Simplifying
k = 60

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