3(k-5)=2(k+5)=

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Solution for 3(k-5)=2(k+5)= equation: 



3(k-5)=2(k+5)=

We move all terms to the left:

3(k-5)-(2(k+5))=0

We multiply parentheses

3k-(2(k+5))-15=0



We calculate terms in parentheses: -(2(k+5)), so:

2(k+5)

We multiply parentheses

2k+10

Back to the equation:

-(2k+10)



We get rid of parentheses

3k-2k-10-15=0

We add all the numbers together, and all the variables

k-25=0

We move all terms containing k to the left, all other terms to the right

k=25

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