3(k-5)=21

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Solution for 3(k-5)=21 equation: 



3(k-5)=21

We move all terms to the left:

3(k-5)-(21)=0

We multiply parentheses

3k-15-21=0

We add all the numbers together, and all the variables

3k-36=0

We move all terms containing k to the left, all other terms to the right

3k=36

k=36/3

k=12

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