3(k-5)=6(k-2)

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Solution for 3(k-5)=6(k-2) equation: 



3(k-5)=6(k-2)

We move all terms to the left:

3(k-5)-(6(k-2))=0

We multiply parentheses

3k-(6(k-2))-15=0



We calculate terms in parentheses: -(6(k-2)), so:

6(k-2)

We multiply parentheses

6k-12

Back to the equation:

-(6k-12)



We get rid of parentheses

3k-6k+12-15=0

We add all the numbers together, and all the variables

-3k-3=0

We move all terms containing k to the left, all other terms to the right

-3k=3

k=3/-3

k=-1

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