3(k-6)-2(3k+9)=4(k+1)-(k-2)

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Solution for 3(k-6)-2(3k+9)=4(k+1)-(k-2) equation: 



3(k-6)-2(3k+9)=4(k+1)-(k-2)

We move all terms to the left:

3(k-6)-2(3k+9)-(4(k+1)-(k-2))=0

We multiply parentheses

3k-6k-(4(k+1)-(k-2))-18-18=0



We calculate terms in parentheses: -(4(k+1)-(k-2)), so:

4(k+1)-(k-2)

We multiply parentheses

4k-(k-2)+4

We get rid of parentheses

4k-k+2+4

We add all the numbers together, and all the variables

3k+6

Back to the equation:

-(3k+6)



We add all the numbers together, and all the variables

-3k-(3k+6)-36=0

We get rid of parentheses

-3k-3k-6-36=0

We add all the numbers together, and all the variables

-6k-42=0

We move all terms containing k to the left, all other terms to the right

-6k=42

k=42/-6

k=-7

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