3(k-7)+8=-4(3-k)

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Solution for 3(k-7)+8=-4(3-k) equation: 



3(k-7)+8=-4(3-k)

We move all terms to the left:

3(k-7)+8-(-4(3-k))=0

We add all the numbers together, and all the variables

3(k-7)-(-4(-1k+3))+8=0

We multiply parentheses

3k-(-4(-1k+3))-21+8=0



We calculate terms in parentheses: -(-4(-1k+3)), so:

-4(-1k+3)

We multiply parentheses

4k-12

Back to the equation:

-(4k-12)



We add all the numbers together, and all the variables

3k-(4k-12)-13=0

We get rid of parentheses

3k-4k+12-13=0

We add all the numbers together, and all the variables

-1k-1=0

We move all terms containing k to the left, all other terms to the right

-k=1

k=1/-1

k=-1

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