3(l+1)=2(l-5)

Solution for 3(l+1)=2(l-5) equation:

Simplifying
3(l + 1) = 2(l + -5)

Reorder the terms:
3(1 + l) = 2(l + -5)
(1 * 3 + l * 3) = 2(l + -5)
(3 + 3l) = 2(l + -5)

Reorder the terms:
3 + 3l = 2(-5 + l)
3 + 3l = (-5 * 2 + l * 2)
3 + 3l = (-10 + 2l)

Solving
3 + 3l = -10 + 2l

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-2l' to each side of the equation.
3 + 3l + -2l = -10 + 2l + -2l

Combine like terms: 3l + -2l = 1l
3 + 1l = -10 + 2l + -2l

Combine like terms: 2l + -2l = 0
3 + 1l = -10 + 0
3 + 1l = -10

Add '-3' to each side of the equation.
3 + -3 + 1l = -10 + -3

Combine like terms: 3 + -3 = 0
0 + 1l = -10 + -3
1l = -10 + -3

Combine like terms: -10 + -3 = -13
1l = -13

Divide each side by '1'.
l = -13

Simplifying
l = -13