3(m+)2=4(2m-1)

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Solution for 3(m+)2=4(2m-1) equation:



3(m+)2=4(2m-1)
We move all terms to the left:
3(m+)2-(4(2m-1))=0
We add all the numbers together, and all the variables
3(+m)2-(4(2m-1))=0
We multiply parentheses
6m-(4(2m-1))=0
We calculate terms in parentheses: -(4(2m-1)), so:
4(2m-1)
We multiply parentheses
8m-4
Back to the equation:
-(8m-4)
We get rid of parentheses
6m-8m+4=0
We add all the numbers together, and all the variables
-2m+4=0
We move all terms containing m to the left, all other terms to the right
-2m=-4
m=-4/-2
m=+2

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