3(m+)2=4(2m-1)

Solution for 3(m+)2=4(2m-1) equation:

3(m+)2=4(2m-1)

We move all terms to the left:

3(m+)2-(4(2m-1))=0

We add all the numbers together, and all the variables

3(+m)2-(4(2m-1))=0

We multiply parentheses

6m-(4(2m-1))=0


We calculate terms in parentheses: -(4(2m-1)), so:

4(2m-1)

We multiply parentheses

8m-4

Back to the equation:

-(8m-4)


We get rid of parentheses

6m-8m+4=0

We add all the numbers together, and all the variables

-2m+4=0

We move all terms containing m to the left, all other terms to the right

-2m=-4

m=-4/-2

m=+2