3(m+1)+2(m+2)=5

Solution for 3(m+1)+2(m+2)=5 equation:

Simplifying
3(m + 1) + 2(m + 2) = 5

Reorder the terms:
3(1 + m) + 2(m + 2) = 5
(1 * 3 + m * 3) + 2(m + 2) = 5
(3 + 3m) + 2(m + 2) = 5

Reorder the terms:
3 + 3m + 2(2 + m) = 5
3 + 3m + (2 * 2 + m * 2) = 5
3 + 3m + (4 + 2m) = 5

Reorder the terms:
3 + 4 + 3m + 2m = 5

Combine like terms: 3 + 4 = 7
7 + 3m + 2m = 5

Combine like terms: 3m + 2m = 5m
7 + 5m = 5

Solving
7 + 5m = 5

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + 5m = 5 + -7

Combine like terms: 7 + -7 = 0
0 + 5m = 5 + -7
5m = 5 + -7

Combine like terms: 5 + -7 = -2
5m = -2

Divide each side by '5'.
m = -0.4

Simplifying
m = -0.4