3(m+1)-2(m-3)=2-4(m-2)

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Solution for 3(m+1)-2(m-3)=2-4(m-2) equation: 



3(m+1)-2(m-3)=2-4(m-2)

We move all terms to the left:

3(m+1)-2(m-3)-(2-4(m-2))=0

We multiply parentheses

3m-2m-(2-4(m-2))+3+6=0



We calculate terms in parentheses: -(2-4(m-2)), so:

2-4(m-2)

determiningTheFunctionDomain
-4(m-2)+2

We multiply parentheses

-4m+8+2

We add all the numbers together, and all the variables

-4m+10

Back to the equation:

-(-4m+10)



We add all the numbers together, and all the variables

m-(-4m+10)+9=0

We get rid of parentheses

m+4m-10+9=0

We add all the numbers together, and all the variables

5m-1=0

We move all terms containing m to the left, all other terms to the right

5m=1

m=1/5

m=1/5

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