3(m+1)=4(m+3)

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Solution for 3(m+1)=4(m+3) equation: 



3(m+1)=4(m+3)

We move all terms to the left:

3(m+1)-(4(m+3))=0

We multiply parentheses

3m-(4(m+3))+3=0



We calculate terms in parentheses: -(4(m+3)), so:

4(m+3)

We multiply parentheses

4m+12

Back to the equation:

-(4m+12)



We get rid of parentheses

3m-4m-12+3=0

We add all the numbers together, and all the variables

-1m-9=0

We move all terms containing m to the left, all other terms to the right

-m=9

m=9/-1

m=-9

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