3(m+1)=6(m-8)

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Solution for 3(m+1)=6(m-8) equation: 



3(m+1)=6(m-8)

We move all terms to the left:

3(m+1)-(6(m-8))=0

We multiply parentheses

3m-(6(m-8))+3=0



We calculate terms in parentheses: -(6(m-8)), so:

6(m-8)

We multiply parentheses

6m-48

Back to the equation:

-(6m-48)



We get rid of parentheses

3m-6m+48+3=0

We add all the numbers together, and all the variables

-3m+51=0

We move all terms containing m to the left, all other terms to the right

-3m=-51

m=-51/-3

m=+17

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