3(m+2)+3=-2(2m-1)

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Solution for 3(m+2)+3=-2(2m-1) equation:



3(m+2)+3=-2(2m-1)
We move all terms to the left:
3(m+2)+3-(-2(2m-1))=0
We multiply parentheses
3m-(-2(2m-1))+6+3=0
We calculate terms in parentheses: -(-2(2m-1)), so:
-2(2m-1)
We multiply parentheses
-4m+2
Back to the equation:
-(-4m+2)
We add all the numbers together, and all the variables
3m-(-4m+2)+9=0
We get rid of parentheses
3m+4m-2+9=0
We add all the numbers together, and all the variables
7m+7=0
We move all terms containing m to the left, all other terms to the right
7m=-7
m=-7/7
m=-1

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