3(m+2)+4(m-1)=12

Solution for 3(m+2)+4(m-1)=12 equation:

Simplifying
3(m + 2) + 4(m + -1) = 12

Reorder the terms:
3(2 + m) + 4(m + -1) = 12
(2 * 3 + m * 3) + 4(m + -1) = 12
(6 + 3m) + 4(m + -1) = 12

Reorder the terms:
6 + 3m + 4(-1 + m) = 12
6 + 3m + (-1 * 4 + m * 4) = 12
6 + 3m + (-4 + 4m) = 12

Reorder the terms:
6 + -4 + 3m + 4m = 12

Combine like terms: 6 + -4 = 2
2 + 3m + 4m = 12

Combine like terms: 3m + 4m = 7m
2 + 7m = 12

Solving
2 + 7m = 12

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 7m = 12 + -2

Combine like terms: 2 + -2 = 0
0 + 7m = 12 + -2
7m = 12 + -2

Combine like terms: 12 + -2 = 10
7m = 10

Divide each side by '7'.
m = 1.428571429

Simplifying
m = 1.428571429