3(m+2)+4=m+20

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Solution for 3(m+2)+4=m+20 equation: 



3(m+2)+4=m+20

We move all terms to the left:

3(m+2)+4-(m+20)=0

We multiply parentheses

3m-(m+20)+6+4=0

We get rid of parentheses

3m-m-20+6+4=0

We add all the numbers together, and all the variables

2m-10=0

We move all terms containing m to the left, all other terms to the right

2m=10

m=10/2

m=5

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