3(m+2)+5(m-1)=2-3(m+1)

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Solution for 3(m+2)+5(m-1)=2-3(m+1) equation: 



3(m+2)+5(m-1)=2-3(m+1)

We move all terms to the left:

3(m+2)+5(m-1)-(2-3(m+1))=0

We multiply parentheses

3m+5m-(2-3(m+1))+6-5=0



We calculate terms in parentheses: -(2-3(m+1)), so:

2-3(m+1)

determiningTheFunctionDomain
-3(m+1)+2

We multiply parentheses

-3m-3+2

We add all the numbers together, and all the variables

-3m-1

Back to the equation:

-(-3m-1)



We add all the numbers together, and all the variables

8m-(-3m-1)+1=0

We get rid of parentheses

8m+3m+1+1=0

We add all the numbers together, and all the variables

11m+2=0

We move all terms containing m to the left, all other terms to the right

11m=-2

m=-2/11

m=-2/11

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