3(m+2)+6=2(m-4)+5m

Solution for 3(m+2)+6=2(m-4)+5m equation:

3(m+2)+6=2(m-4)+5m

We move all terms to the left:

3(m+2)+6-(2(m-4)+5m)=0

We multiply parentheses

3m-(2(m-4)+5m)+6+6=0


We calculate terms in parentheses: -(2(m-4)+5m), so:

2(m-4)+5m

We add all the numbers together, and all the variables

5m+2(m-4)

We multiply parentheses

5m+2m-8

We add all the numbers together, and all the variables

7m-8

Back to the equation:

-(7m-8)


We add all the numbers together, and all the variables

3m-(7m-8)+12=0

We get rid of parentheses

3m-7m+8+12=0

We add all the numbers together, and all the variables

-4m+20=0

We move all terms containing m to the left, all other terms to the right

-4m=-20

m=-20/-4

m=+5