3(m+2)-6(m-1)=20

Solution for 3(m+2)-6(m-1)=20 equation:

Simplifying
3(m + 2) + -6(m + -1) = 20

Reorder the terms:
3(2 + m) + -6(m + -1) = 20
(2 * 3 + m * 3) + -6(m + -1) = 20
(6 + 3m) + -6(m + -1) = 20

Reorder the terms:
6 + 3m + -6(-1 + m) = 20
6 + 3m + (-1 * -6 + m * -6) = 20
6 + 3m + (6 + -6m) = 20

Reorder the terms:
6 + 6 + 3m + -6m = 20

Combine like terms: 6 + 6 = 12
12 + 3m + -6m = 20

Combine like terms: 3m + -6m = -3m
12 + -3m = 20

Solving
12 + -3m = 20

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + -3m = 20 + -12

Combine like terms: 12 + -12 = 0
0 + -3m = 20 + -12
-3m = 20 + -12

Combine like terms: 20 + -12 = 8
-3m = 8

Divide each side by '-3'.
m = -2.666666667

Simplifying
m = -2.666666667