3(m+2)=.25(12m+24)

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Solution for 3(m+2)=.25(12m+24) equation:


Simplifying
3(m + 2) = 0.25(12m + 24)

Reorder the terms:
3(2 + m) = 0.25(12m + 24)
(2 * 3 + m * 3) = 0.25(12m + 24)
(6 + 3m) = 0.25(12m + 24)

Reorder the terms:
6 + 3m = 0.25(24 + 12m)
6 + 3m = (24 * 0.25 + 12m * 0.25)
6 + 3m = (6 + 3m)

Add '-6' to each side of the equation.
6 + -6 + 3m = 6 + -6 + 3m

Combine like terms: 6 + -6 = 0
0 + 3m = 6 + -6 + 3m
3m = 6 + -6 + 3m

Combine like terms: 6 + -6 = 0
3m = 0 + 3m
3m = 3m

Add '-3m' to each side of the equation.
3m + -3m = 3m + -3m

Combine like terms: 3m + -3m = 0
0 = 3m + -3m

Combine like terms: 3m + -3m = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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