3(m+2)=12(m-2)

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Solution for 3(m+2)=12(m-2) equation:



3(m+2)=12(m-2)
We move all terms to the left:
3(m+2)-(12(m-2))=0
We multiply parentheses
3m-(12(m-2))+6=0
We calculate terms in parentheses: -(12(m-2)), so:
12(m-2)
We multiply parentheses
12m-24
Back to the equation:
-(12m-24)
We get rid of parentheses
3m-12m+24+6=0
We add all the numbers together, and all the variables
-9m+30=0
We move all terms containing m to the left, all other terms to the right
-9m=-30
m=-30/-9
m=3+1/3

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