3(m+2)=2(m+3)+m

Solution for 3(m+2)=2(m+3)+m equation:

Simplifying
3(m + 2) = 2(m + 3) + m

Reorder the terms:
3(2 + m) = 2(m + 3) + m
(2 * 3 + m * 3) = 2(m + 3) + m
(6 + 3m) = 2(m + 3) + m

Reorder the terms:
6 + 3m = 2(3 + m) + m
6 + 3m = (3 * 2 + m * 2) + m
6 + 3m = (6 + 2m) + m

Combine like terms: 2m + m = 3m
6 + 3m = 6 + 3m

Add '-6' to each side of the equation.
6 + -6 + 3m = 6 + -6 + 3m

Combine like terms: 6 + -6 = 0
0 + 3m = 6 + -6 + 3m
3m = 6 + -6 + 3m

Combine like terms: 6 + -6 = 0
3m = 0 + 3m
3m = 3m

Add '-3m' to each side of the equation.
3m + -3m = 3m + -3m

Combine like terms: 3m + -3m = 0
0 = 3m + -3m

Combine like terms: 3m + -3m = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.