3(m+2)=2(m-1)=

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Solution for 3(m+2)=2(m-1)= equation: 



3(m+2)=2(m-1)=

We move all terms to the left:

3(m+2)-(2(m-1))=0

We multiply parentheses

3m-(2(m-1))+6=0



We calculate terms in parentheses: -(2(m-1)), so:

2(m-1)

We multiply parentheses

2m-2

Back to the equation:

-(2m-2)



We get rid of parentheses

3m-2m+2+6=0

We add all the numbers together, and all the variables

m+8=0

We move all terms containing m to the left, all other terms to the right

m=-8

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