3(m+2)=4(5+m)

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Solution for 3(m+2)=4(5+m) equation: 



3(m+2)=4(5+m)

We move all terms to the left:

3(m+2)-(4(5+m))=0

We add all the numbers together, and all the variables

3(m+2)-(4(m+5))=0

We multiply parentheses

3m-(4(m+5))+6=0



We calculate terms in parentheses: -(4(m+5)), so:

4(m+5)

We multiply parentheses

4m+20

Back to the equation:

-(4m+20)



We get rid of parentheses

3m-4m-20+6=0

We add all the numbers together, and all the variables

-1m-14=0

We move all terms containing m to the left, all other terms to the right

-m=14

m=14/-1

m=-14

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