3(m+2)=6(2m-5)

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Solution for 3(m+2)=6(2m-5) equation: 



3(m+2)=6(2m-5)

We move all terms to the left:

3(m+2)-(6(2m-5))=0

We multiply parentheses

3m-(6(2m-5))+6=0



We calculate terms in parentheses: -(6(2m-5)), so:

6(2m-5)

We multiply parentheses

12m-30

Back to the equation:

-(12m-30)



We get rid of parentheses

3m-12m+30+6=0

We add all the numbers together, and all the variables

-9m+36=0

We move all terms containing m to the left, all other terms to the right

-9m=-36

m=-36/-9

m=+4

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