3(m+2)=m+2m-4-10

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Solution for 3(m+2)=m+2m-4-10 equation:


Simplifying
3(m + 2) = m + 2m + -4 + -10

Reorder the terms:
3(2 + m) = m + 2m + -4 + -10
(2 * 3 + m * 3) = m + 2m + -4 + -10
(6 + 3m) = m + 2m + -4 + -10

Reorder the terms:
6 + 3m = -4 + -10 + m + 2m

Combine like terms: -4 + -10 = -14
6 + 3m = -14 + m + 2m

Combine like terms: m + 2m = 3m
6 + 3m = -14 + 3m

Add '-3m' to each side of the equation.
6 + 3m + -3m = -14 + 3m + -3m

Combine like terms: 3m + -3m = 0
6 + 0 = -14 + 3m + -3m
6 = -14 + 3m + -3m

Combine like terms: 3m + -3m = 0
6 = -14 + 0
6 = -14

Solving
6 = -14

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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