3(m+3)+12=2(m+10)

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Solution for 3(m+3)+12=2(m+10) equation:


Simplifying
3(m + 3) + 12 = 2(m + 10)

Reorder the terms:
3(3 + m) + 12 = 2(m + 10)
(3 * 3 + m * 3) + 12 = 2(m + 10)
(9 + 3m) + 12 = 2(m + 10)

Reorder the terms:
9 + 12 + 3m = 2(m + 10)

Combine like terms: 9 + 12 = 21
21 + 3m = 2(m + 10)

Reorder the terms:
21 + 3m = 2(10 + m)
21 + 3m = (10 * 2 + m * 2)
21 + 3m = (20 + 2m)

Solving
21 + 3m = 20 + 2m

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-2m' to each side of the equation.
21 + 3m + -2m = 20 + 2m + -2m

Combine like terms: 3m + -2m = 1m
21 + 1m = 20 + 2m + -2m

Combine like terms: 2m + -2m = 0
21 + 1m = 20 + 0
21 + 1m = 20

Add '-21' to each side of the equation.
21 + -21 + 1m = 20 + -21

Combine like terms: 21 + -21 = 0
0 + 1m = 20 + -21
1m = 20 + -21

Combine like terms: 20 + -21 = -1
1m = -1

Divide each side by '1'.
m = -1

Simplifying
m = -1

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