3(m+4)-5=4(m-2)

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Solution for 3(m+4)-5=4(m-2) equation: 



3(m+4)-5=4(m-2)

We move all terms to the left:

3(m+4)-5-(4(m-2))=0

We multiply parentheses

3m-(4(m-2))+12-5=0



We calculate terms in parentheses: -(4(m-2)), so:

4(m-2)

We multiply parentheses

4m-8

Back to the equation:

-(4m-8)



We add all the numbers together, and all the variables

3m-(4m-8)+7=0

We get rid of parentheses

3m-4m+8+7=0

We add all the numbers together, and all the variables

-1m+15=0

We move all terms containing m to the left, all other terms to the right

-m=-15

m=-15/-1

m=+15

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