3(m+5)+4m=10(m-8)+2m

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Solution for 3(m+5)+4m=10(m-8)+2m equation: 



3(m+5)+4m=10(m-8)+2m

We move all terms to the left:

3(m+5)+4m-(10(m-8)+2m)=0

We add all the numbers together, and all the variables

4m+3(m+5)-(10(m-8)+2m)=0

We multiply parentheses

4m+3m-(10(m-8)+2m)+15=0



We calculate terms in parentheses: -(10(m-8)+2m), so:

10(m-8)+2m

We add all the numbers together, and all the variables

2m+10(m-8)

We multiply parentheses

2m+10m-80

We add all the numbers together, and all the variables

12m-80

Back to the equation:

-(12m-80)



We add all the numbers together, and all the variables

7m-(12m-80)+15=0

We get rid of parentheses

7m-12m+80+15=0

We add all the numbers together, and all the variables

-5m+95=0

We move all terms containing m to the left, all other terms to the right

-5m=-95

m=-95/-5

m=+19

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