3(m+5)=(6-2)+10

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Solution for 3(m+5)=(6-2)+10 equation: 



3(m+5)=(6-2)+10

We move all terms to the left:

3(m+5)-((6-2)+10)=0

We add all the numbers together, and all the variables

3(m+5)-(4+10)=0

We add all the numbers together, and all the variables

3(m+5)-14=0

We multiply parentheses

3m+15-14=0

We add all the numbers together, and all the variables

3m+1=0

We move all terms containing m to the left, all other terms to the right

3m=-1

m=-1/3

m=-1/3

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