3(m+5)=2(m-7)

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Solution for 3(m+5)=2(m-7) equation: 



3(m+5)=2(m-7)

We move all terms to the left:

3(m+5)-(2(m-7))=0

We multiply parentheses

3m-(2(m-7))+15=0



We calculate terms in parentheses: -(2(m-7)), so:

2(m-7)

We multiply parentheses

2m-14

Back to the equation:

-(2m-14)



We get rid of parentheses

3m-2m+14+15=0

We add all the numbers together, and all the variables

m+29=0

We move all terms containing m to the left, all other terms to the right

m=-29

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