3(m+5)=3+3(2m+2)

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Solution for 3(m+5)=3+3(2m+2) equation: 



3(m+5)=3+3(2m+2)

We move all terms to the left:

3(m+5)-(3+3(2m+2))=0

We multiply parentheses

3m-(3+3(2m+2))+15=0



We calculate terms in parentheses: -(3+3(2m+2)), so:

3+3(2m+2)

determiningTheFunctionDomain
3(2m+2)+3

We multiply parentheses

6m+6+3

We add all the numbers together, and all the variables

6m+9

Back to the equation:

-(6m+9)



We get rid of parentheses

3m-6m-9+15=0

We add all the numbers together, and all the variables

-3m+6=0

We move all terms containing m to the left, all other terms to the right

-3m=-6

m=-6/-3

m=+2

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