3(m-1)+m=2(m-1)

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Solution for 3(m-1)+m=2(m-1) equation:


Simplifying
3(m + -1) + m = 2(m + -1)

Reorder the terms:
3(-1 + m) + m = 2(m + -1)
(-1 * 3 + m * 3) + m = 2(m + -1)
(-3 + 3m) + m = 2(m + -1)

Combine like terms: 3m + m = 4m
-3 + 4m = 2(m + -1)

Reorder the terms:
-3 + 4m = 2(-1 + m)
-3 + 4m = (-1 * 2 + m * 2)
-3 + 4m = (-2 + 2m)

Solving
-3 + 4m = -2 + 2m

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-2m' to each side of the equation.
-3 + 4m + -2m = -2 + 2m + -2m

Combine like terms: 4m + -2m = 2m
-3 + 2m = -2 + 2m + -2m

Combine like terms: 2m + -2m = 0
-3 + 2m = -2 + 0
-3 + 2m = -2

Add '3' to each side of the equation.
-3 + 3 + 2m = -2 + 3

Combine like terms: -3 + 3 = 0
0 + 2m = -2 + 3
2m = -2 + 3

Combine like terms: -2 + 3 = 1
2m = 1

Divide each side by '2'.
m = 0.5

Simplifying
m = 0.5

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