3(m-19)+12=-3

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Solution for 3(m-19)+12=-3 equation: 



3(m-19)+12=-3

We move all terms to the left:

3(m-19)+12-(-3)=0

We add all the numbers together, and all the variables

3(m-19)+15=0

We multiply parentheses

3m-57+15=0

We add all the numbers together, and all the variables

3m-42=0

We move all terms containing m to the left, all other terms to the right

3m=42

m=42/3

m=14

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