3(m-2)=2(m+1)+m

Solution for 3(m-2)=2(m+1)+m equation:

Simplifying
3(m + -2) = 2(m + 1) + m

Reorder the terms:
3(-2 + m) = 2(m + 1) + m
(-2 * 3 + m * 3) = 2(m + 1) + m
(-6 + 3m) = 2(m + 1) + m

Reorder the terms:
-6 + 3m = 2(1 + m) + m
-6 + 3m = (1 * 2 + m * 2) + m
-6 + 3m = (2 + 2m) + m

Combine like terms: 2m + m = 3m
-6 + 3m = 2 + 3m

Add '-3m' to each side of the equation.
-6 + 3m + -3m = 2 + 3m + -3m

Combine like terms: 3m + -3m = 0
-6 + 0 = 2 + 3m + -3m
-6 = 2 + 3m + -3m

Combine like terms: 3m + -3m = 0
-6 = 2 + 0
-6 = 2

Solving
-6 = 2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.