3(m-5)+1=2(m+2)-18

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Solution for 3(m-5)+1=2(m+2)-18 equation:


Simplifying
3(m + -5) + 1 = 2(m + 2) + -18

Reorder the terms:
3(-5 + m) + 1 = 2(m + 2) + -18
(-5 * 3 + m * 3) + 1 = 2(m + 2) + -18
(-15 + 3m) + 1 = 2(m + 2) + -18

Reorder the terms:
-15 + 1 + 3m = 2(m + 2) + -18

Combine like terms: -15 + 1 = -14
-14 + 3m = 2(m + 2) + -18

Reorder the terms:
-14 + 3m = 2(2 + m) + -18
-14 + 3m = (2 * 2 + m * 2) + -18
-14 + 3m = (4 + 2m) + -18

Reorder the terms:
-14 + 3m = 4 + -18 + 2m

Combine like terms: 4 + -18 = -14
-14 + 3m = -14 + 2m

Add '14' to each side of the equation.
-14 + 14 + 3m = -14 + 14 + 2m

Combine like terms: -14 + 14 = 0
0 + 3m = -14 + 14 + 2m
3m = -14 + 14 + 2m

Combine like terms: -14 + 14 = 0
3m = 0 + 2m
3m = 2m

Solving
3m = 2m

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-2m' to each side of the equation.
3m + -2m = 2m + -2m

Combine like terms: 3m + -2m = 1m
1m = 2m + -2m

Combine like terms: 2m + -2m = 0
1m = 0

Divide each side by '1'.
m = 0

Simplifying
m = 0

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