3(m-5)+m=1

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Solution for 3(m-5)+m=1 equation: 



3(m-5)+m=1

We move all terms to the left:

3(m-5)+m-(1)=0

We add all the numbers together, and all the variables

m+3(m-5)-1=0

We multiply parentheses

m+3m-15-1=0

We add all the numbers together, and all the variables

4m-16=0

We move all terms containing m to the left, all other terms to the right

4m=16

m=16/4

m=4

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